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| class Solution {
public int rob(int[] nums) {
if (nums == null || nums.length == 0) {
return 0;
}
int n = nums.length;
if (n == 1) {
return nums[0];
}
int left = robRange(Arrays.copyOfRange(nums, 1, n));
int right = robRange(Arrays.copyOfRange(nums, 0, n - 1));
return Math.max(left, right);
}
public int robRange(int[] nums) {
if (nums == null || nums.length == 0) {
return 0;
}
int n = nums.length;
if (n == 1) {
return nums[0];
}
int[] dp = new int[n]; // dp[i] 表示偷窃前 i 个房屋所能获得的最高金额
dp[0] = nums[0];
dp[1] = Math.max(nums[0], nums[1]);
for (int i = 2; i < n; i++) {
dp[i] = Math.max(dp[i - 1], dp[i - 2] + nums[i]);
}
return dp[n - 1];
}
}
|