LeetCode 445. 两数相加 II
题目描述
思路分析
加法问题
参考代码
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func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode {
if l1 == nil {
return l2
} else if l2 == nil {
return l1
}
l1, l2 = reverse(l1), reverse(l2)
var pre *ListNode
carry := 0
for l1 != nil || l2 != nil || carry > 0 {
sum := carry
if l1 != nil {
sum += l1.Val
l1 = l1.Next
}
if l2 != nil {
sum += l2.Val
l2 = l2.Next
}
carry = sum / 10
cur := &ListNode{Val: sum % 10}
cur.Next = pre
pre = cur
}
return pre
}
func reverse(head *ListNode) *ListNode {
if head == nil || head.Next == nil {
return head
}
var pre *ListNode
cur := head
for cur != nil {
node := cur.Next
cur.Next = pre
pre = cur
cur = node
}
return pre
}
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func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode {
if l1 == nil {
return l2
} else if l2 == nil {
return l1
}
stack1, stack2 := []int{}, []int{}
for l1 != nil {
stack1 = append(stack1, l1.Val)
l1 = l1.Next
}
for l2 != nil {
stack2 = append(stack2, l2.Val)
l2 = l2.Next
}
var pre *ListNode
carry := 0
for len(stack1) > 0 || len(stack2) > 0 || carry > 0 {
sum := carry
if len(stack1) > 0 {
sum += stack1[len(stack1)-1]
stack1 = stack1[:len(stack1)-1]
}
if len(stack2) > 0 {
sum += stack2[len(stack2)-1]
stack2 = stack2[:len(stack2)-1]
}
carry = sum / 10
sum = sum % 10
cur := &ListNode{Val: sum}
cur.Next = pre
pre = cur
}
return pre
}
1
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