LeetCode 面试题 02.08. 环路检测
题目描述
思路分析
快慢指针
参考代码
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func detectCycle(head *ListNode) *ListNode {
if head == nil || head.Next == nil {
return nil
}
slow, fast := head, head
for fast != nil && fast.Next != nil {
slow = slow.Next
fast = fast.Next.Next
if slow == fast {
slow = head
for slow != fast {
slow = slow.Next
fast = fast.Next
}
return slow
}
}
return nil
}
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