LeetCode 232. 用栈实现队列
题目描述
思路分析
思路描述
参考代码
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type MyQueue struct {
inStack []int
outStack []int
}
func Constructor() MyQueue {
return MyQueue{}
}
func (q *MyQueue) Push(x int) {
q.inStack = append(q.inStack, x)
}
func (q *MyQueue) Pop() int {
val := q.Peek()
q.outStack = q.outStack[:len(q.outStack)-1]
return val
}
func (q *MyQueue) Peek() int {
if len(q.outStack) == 0 {
for len(q.inStack) > 0 {
q.outStack = append(q.outStack, q.inStack[len(q.inStack)-1])
q.inStack = q.inStack[:len(q.inStack)-1]
}
}
return q.outStack[len(q.outStack)-1]
}
func (q *MyQueue) Empty() bool {
return len(q.inStack) == 0 && len(q.outStack) == 0
}
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class MyQueue {
private Stack<Integer> stack1;
private Stack<Integer> stack2;
public MyQueue() {
stack1 = new Stack<>();
stack2 = new Stack<>();
}
public void push(int x) {
stack1.push(x);
}
public int pop() {
peek();
return stack2.pop();
}
public int peek() {
if (stack2.isEmpty()) {
while (!stack1.isEmpty()) {
stack2.push(stack1.pop());
}
}
return stack2.peek();
}
public boolean empty() {
return stack1.isEmpty() && stack2.isEmpty();
}
}
相似题目
题目 | 难度 | 题解 |
---|---|---|
用队列实现栈 | Easy |
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