LeetCode 剑指 Offer 51. 数组中的逆序对
题目描述
考察公司:小米
考察时间:2025.05.26
思路分析
归并排序
参考代码
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func reversePairs(nums []int) int {
if len(nums) <= 1 {
return 0
}
var merge func(nums []int, left, right int) int
merge = func(nums []int, left, right int) int {
if left >= right {
return 0
}
mid := left + (right-left)/2
count := merge(nums, left, mid) + merge(nums, mid+1, right)
i, j := left, mid+1
k := 0
res := make([]int, right-left+1)
for i <= mid && j <= right {
if nums[i] <= nums[j] {
res[k] = nums[i]
i++
} else {
res[k] = nums[j]
j++
count += mid - i + 1
}
k++
}
for i <= mid {
res[k] = nums[i]
i++
k++
}
for j <= right {
res[k] = nums[j]
j++
k++
}
for p := 0; p < len(res); p++ {
nums[left+p] = res[p]
}
return count
}
res := merge(nums, 0, len(nums)-1)
return res
}
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